Huntington Beach, known for its world-class surfing beaches, is the most expensive city in California based on the cost of lodging. That’s the result of a survey conducted by LosAngelesHotels.org, which compared hotel rates of 30 urban destinations in the Golden State.
Specifically, for each destination, the survey established the average price for the cheapest available double room during September and October 2019, the months when most cities in California reach their highest average hotel rates. Only centrally-located hotels rated at least 3 stars were included in the survey.
At an average $223 per night for the least expensive room rates, Huntington Beach leads the rankings. San Jose and neighboring Sunnyvale, both located in Santa Clara County, complete the podium with average room rates of $198 and $193 per night, respectively. San Francisco ranks fifth most-expensive, with an average room rate of $184 per night.
Significantly more affordable are Los Angeles and San Diego, where travelers can spend as little as $126 and $114 per night for a room, respectively. The least expensive destination overall in California, according to hotel room rates, is Santa Rosa, located in Sonoma County, at an average of $92 per night.
The following table shows the 10 most-expensive urban destinations in California. The prices shown reflect the average room rates for each destination's cheapest available double rooms, Sept. 1–Oct. 30, 2019.
1. Huntington Beach $223
2. San Jose $198
3. Sunnyvale $193
4. Oakland $186
5. San Francisco $184
6. Santa Clarita $165
7. Sacramento $158
8. Riverside $153
9. San Bernardino $153
10. Fremont $15
2. San Jose $198
3. Sunnyvale $193
4. Oakland $186
5. San Francisco $184
6. Santa Clarita $165
7. Sacramento $158
8. Riverside $153
9. San Bernardino $153
10. Fremont $15
Tags: LosAngelesHotels.org
